Physics - Gravitation Question with Solution | TestHub

On an artificial satellite orbiting the earth the acceleration is given by $\frac{GM}{R^2}$ towards the centre of the earth. Now for a body of mass $m$ on the satellite the graviational force due to earth is $\frac{GMm}{R^2}$ towards the centre of the earth. Let the reaction force on the surface of the satellite be $N$, then $\frac{GMm}{R^2}-N=m\left(\frac{GM}{R^2}\right)$ $\Rightarrow N=0$ That is on the satellite there is a state of weightlessness or $g=0$ $\therefore$ The time period of the simple pendulum, $T=2\pi \sqrt{\frac{l}{g}}=\infty$