Physics - Gravitation Question with Solution | TestHub

Geo-stationary satellites are also called synchronous satellite. They always remain about the same path on equater, i.e., it has a period of exactly one day $(86400\sec )$ So orbit radius $\left(\mathrm{T}=2\pi \sqrt{\frac{{\mathrm{r}}^3}{\mathrm{GM}}}\right)$ comes out to be $42400\mathrm{km}$, which is nearly equal to the circumference of earth. So height of Geostationary satellite from the earth $$\text{ surface is }42,400-6400=36,000\mathrm{km}\text{ . }$$