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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationEnergy & PotentialMedium2 minPYQ_2002

PhysicsMediumsingle choice

A body of mass $m$ is placed on Earth's surface which is a taken from Earth's surface to a height of $h = 3 R$ , then the change in the gravitational potential energy is:

Options:

Answer:

Solution:

$∴ change in GPE = final energy - initial energy = - \frac{GM m}{4 R} + \frac{GMm}{R} = - \frac{GM m}{4 R} [1 - \frac{1}{4}] = \frac{3}{4} \frac{GM m}{4 R} = \frac{3}{4} \frac{GM}{R ^{2}} m R = \frac{3}{4} g m R$

Stream:NEETSubject:PhysicsTopic:GravitationSubtopic:Energy & Potential

⏱ 2mℹ️ Source: PYQ_2002

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