Gravitational acceleration on the surface of a planet is 11 6 g , where g is the gravitational acceleration on the surface of the earth. The average mass density of the planet is 3 2 times that

Question

Gravitational acceleration on the surface of a planet is $\frac{6}{11} g$ , where g is the gravitational acceleration on the surface of the earth. The average mass density of the planet is $\frac{2}{3}$ times that of the earth. If the escape speed on the surface of the earth is taken to be $11 kms^{- 1}$ , find the escape speed on the surface of the planet in $kms^{- 1}$ .

Answer:

3.00

Solution:

$g \propto ρR$

$v_{e} = 2 g R$

Use the stated gravity and density ratios to obtain the radius ratio.

$\frac{v _{e, p}}{v _{e, e}} = \frac{3}{11}$

$v_{e, p} = 3.00 km / s$

TestHub · Accepted Answer

g ∝ ρR v e ​ = 2 g R ​ Use the stated gravity and density ratios to obtain the radius ratio. v e , e ​ v e , p ​ ​ = 11 3 ​ v e , p ​ = 3.00 km / s

Physics - Gravitation Question with Solution | TestHub

Doubts & Discussion