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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationField & ForceEasy2 minPDF

PhysicsEasynumerical

A simple pendulum has a time period $T_{1}$ when on earth's surface, and $T_{2}$ when taken at a height 2 R above the earth's surface where R is the radius of earth. The value of $T_{2} / T_{1}$ is :-

Answer:

3.00

Solution:

$T \propto \frac{1}{g}$

$g_{h} = g (\frac{R}{R + 2 R})^{2} = \frac{g}{9}$

$\frac{T _{h}}{T _{e}} = \frac{g}{g /9} = 3$

Stream:JEESubject:PhysicsTopic:GravitationSubtopic:Field & Force

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