An object of mass m is thrown vertically upwards from the surface of earth with velocity v. M is mass of earth and R is radius of earth. List - I List - II (P) v = R GM (1) Maximum height reached

Question

An object of mass m is thrown vertically upwards from the surface of earth with velocity v. M is mass of earth and R is radius of earth.

List - I	List - II
(P) $v = \frac{GM}{R}$	(1) Maximum height reached by particle above ground is R.
(Q) $v = \frac{1.5 GM}{R}$	(2) Maximum height reached by particle above ground is 3R.
(R) $v = \frac{2 GM}{R}$	(3) Particle hits the earth again.
(S) $v = \frac{0.5 GM}{R}$	(4) Particle escapes from earth.
	(5) Maximum height reached by particle above ground is R/3.

TestHub · Accepted Answer

2 1 ​ m v 2 − R GM m ​ = − r ma x ​ GM m ​ For P, maximum height is R and the particle returns: P → 1,3. For Q, maximum height is 2R and it returns: Q → 2,3. For R, escape speed is reached: R → 4. For S, maximum height is R/3 and it returns: S → 5,3. Hence option C.

Physics - Gravitation Question with Solution | TestHub

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