Angle of deviation is given in List-I and ray diagram for angle of deviation in List-II. List-I List-II (I) 6 0 ∘ (P) (II) 0 ∘ (Q) (III) 18 0 ∘ (R) (IV) 3 0 ∘ (S) (T) None

Identify the deviation produced by each ray diagram of List-II. A deviation of 6 0 ∘ matches diagram S; 0 ∘ deviation (no bending) matches P; 18 0 ∘ (reversal) matches R; 3 0 ∘ matches Q. So I → S, II → P, III → R, IV → Q, matching option (D). Answer: D

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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsPrismMedium3 min

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Angle of deviation is given in List-I and ray diagram for angle of deviation in List-II.

List-I	List-II
(I) $6 0^{\circ}$	(P)
(II) $0^{\circ}$	(Q)
(III) $18 0^{\circ}$	(R)
(IV) $3 0^{\circ}$	(S)
	(T) None

Options:

Answer:

Solution:

Identify the deviation produced by each ray diagram of List-II.

A deviation of $6 0^{\circ}$ matches diagram S; $0^{\circ}$ deviation (no bending) matches P; $18 0^{\circ}$ (reversal) matches R; $3 0^{\circ}$ matches Q.

So I $\to$ S, II $\to$ P, III $\to$ R, IV $\to$ Q, matching option (D).

Answer: D

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Prism

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