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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsTIR/Prism and DispersionMedium2 minQB

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A prism of refractive index $η$ and angle $A$ is placed in minimum deviation position. If the angle of minimum deviation is equal to the angle $A$ , then the value of $A$ is

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Answer:

Solution:

$η = \frac{sin A}{sin ( A /2 )} = 2 cos \frac{A}{2}$

$cos \frac{A}{2} = \frac{η}{2}$

$sin \frac{A}{2} = 1 - \frac{η ^{2}}{4} = \frac{4 - η ^{2}}{4}$

$A = 2 sin^{- 1} \frac{4 - η ^{2}}{4}$

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:TIR/Prism and Dispersion

⏱ 2mℹ️ Source: QB

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