For a convex lens forming real images, the graph between v 1 ( y -axis) and u 1 ( x -axis), using magnitudes, is

v 1 = − u 1 + f 1 A straight line of slope − 1 with intercept f 1 on each axis.

Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensMedium2 minQB

PhysicsMediumsingle choice

For a convex lens forming real images, the graph between $\frac{1}{v}$ ( $y$ -axis) and $\frac{1}{u}$ ( $x$ -axis), using magnitudes, is

Answer:

Solution:

$\frac{1}{v} = - \frac{1}{u} + \frac{1}{f}$

A straight line of slope $- 1$ with intercept $\frac{1}{f}$ on each axis.

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: QB

Loading discussions...