The graph between v 1 and u 1 for a concave mirror looks like

v 1 + u 1 = f 1 v 1 = − u 1 + f 1 A straight line of slope − 1 making equal intercepts f 1 on both axes: figure (b).

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PhysicsGeometrical OpticsReflection at curved surfaceMedium2 minQB

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The graph between $\frac{1}{v}$ and $\frac{1}{u}$ for a concave mirror looks like

Answer:

Solution:

$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$

$\frac{1}{v} = - \frac{1}{u} + \frac{1}{f}$

A straight line of slope $- 1$ making equal intercepts $\frac{1}{f}$ on both axes: figure (b).

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Reflection at curved surface

⏱ 2mℹ️ Source: QB

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