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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensMedium2 minQB

PhysicsMediummultiple choice

Two lenses $L_{1}$ and $L_{2}$ are arranged as shown in the figure. An object of length 1 cm is kept at a distance of 10 cm in front of the combination. Select the correct options.

Options:(select one or more)

Answer:

A, B

Solution:

$\frac{1}{f} = \frac{1}{f _{1}} + \frac{1}{f _{2}} = \frac{1}{10} + \frac{1}{( - 20 )} = \frac{1}{20}$

$f = 20$ cm

$u = - 10$ cm, $f = + 20$ cm

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$

$\frac{1}{20} = \frac{1}{v} - \frac{1}{- 10} \Rightarrow \frac{1}{v} = \frac{1}{20} - \frac{1}{10}$

$v = - 20$ cm

$m = + \frac{v}{u} = \frac{- 20}{- 10} = + 2$

$\frac{h _{I}}{h _{0}} = 2 \Rightarrow \frac{h _{I}}{1} = 2$

$h_{I} = 2$ cm

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: QB

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