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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsOptical instrumentsMedium2 minQB

PhysicsMediumsingle choice

A compound microscope having objective lens of focal length 2 cm and eyepiece of focal length 2.5 cm , is adjusted for clear vision (LDDV = 25 cm), for which the angular magnification is found to be 110. The tube length must be about

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Solution:

$m = m_{o} \times m_{e}; m_{e} = 1 + D / f_{e} = 1 + 25/2.5 = 11$ . $m_{o} = 110/11 = 10 = v_{o} / u_{o}$ ; with $1/ v_{o} + 1/ u_{o} = 1/2 : u_{o} = 2.2 cm, v_{o} = 22 cm$ . Eyepiece: $1/ u_{e} = 1/ f_{e} + 1/ D = 0.44 \Rightarrow u_{e} = 2.27 cm$ . Tube length $= v_{o} + u_{e} \approx 24.3 cm$ .

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Optical instruments

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