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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensMedium2 minQB

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In an experiment to find the focal length of a convex lens, a graph is drawn between the magnitudes of $u$ and $v$ (both positive for real images). The graph looks like

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Answer:

Solution:

For a convex lens, $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$ (magnitudes, real images)

$v = \frac{u f}{u - f}$

So $v$ decreases non-linearly as $u$ increases: a decreasing curve.

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: QB

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