A prism of refractive index 2 has refracting angle 6 0 ∘ . In order that a ray suffers minimum deviation it should be incident at an angle

At minimum deviation r 1 = A /2 = 3 0 ∘ sin i = 2 sin 3 0 ∘ = 2 1 i = 4 5 ∘

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PhysicsGeometrical OpticsTIR/Prism and DispersionMedium2 minQB

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A prism of refractive index $2$ has refracting angle $6 0^{\circ}$ . In order that a ray suffers minimum deviation it should be incident at an angle

Answer:

Solution:

At minimum deviation $r_{1} = A /2 = 3 0^{\circ}$

$sin i = 2 sin 3 0^{\circ} = \frac{1}{2}$

$i = 4 5^{\circ}$

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:TIR/Prism and Dispersion

⏱ 2mℹ️ Source: QB

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