Physics - Geometrical Optics Question with Solution | TestHub

Take mirror 1 at $x=0$, mirror 2 at $x=d$, candle at $x=0.2d$.

Image in mirror 1: $-0.2d$, so $0.2d$ behind.

Image in mirror $2:2d-0.2d=1.8d$.

Its image in mirror 1 is at $-1.8d$, so $1.8d$ behind.

Image of $-0.2d$ in mirror $2:2d+0.2d=2.2d$.

Its image in mirror 1 is at $-2.2d$.

Nearest three: $0.2d,1.8d,2.2d$.