A spherical surface of radius of curvature R , separates air from glass (refractive index = 1.5 ). The centre of curvature is in the glass medium. A point object ' O ' placed in air on the o

Question

A spherical surface of radius of curvature R , separates air from glass (refractive index = 1.5 ). The centre of curvature is in the glass medium. A point object ' O ' placed in air on the optic axis of the surface, so that its real image is formed at ' I ' inside glass. The line OI intersects the spherical surface at P and PO = PI . The distance PO equals to

TestHub · Accepted Answer

​ PO = u = − x PI = v = x PO = PI v μ 2 ​ ​ − u μ 1 ​ ​ = R μ 2 ​ − μ 1 ​ ​ x 1.5 ​ + x 1 ​ = 2 R 1 ​ 2 x 5 ​ = 2 R 1 ​ X = 5 R ​

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