A glass slab of thickness 4.8 cm is placed on the piece of paper on which an ink dot is marked. By how much distance would an ink dot appear to be raised? ( The refractive index of glass = 1.5 )

Question

TestHub · Accepted Answer

The apparent shift (or the distance by which the ink dot appears to be raised) is given by the formula:

$Δ t = t (1 - \frac{1}{μ})$

where $t$ is the real thickness of the glass slab and $μ$ is the refractive index of the glass.

Given:
$t = 4.8$ cm
$μ = 1.5 = \frac{3}{2}$

Substituting the values into the formula:

$Δ t = 4.8 (1 - \frac{1}{1.5})$

$Δ t = 4.8 (1 - \frac{2}{3})$

$Δ t = 4.8 \times \frac{1}{3}$

$Δ t = 1.6$ cm

Answer: 1.6 cm

Physics - Geometrical Optics Question with Solution | TestHub

Options:

Doubts & Discussion