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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsOptical instrumentsEasy2 minPYQ_2024

PhysicsEasysingle choice

Focal length of objective of an astronomical telescope is 1.5 m . Under normal adjustment, length of telescope is 1.56 m . Focal length of the eyepiece is

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Answer:

Solution:

For an astronomical telescope in normal adjustment, the length of the telescope tube is given by $L = f_{o} + f_{e}$ .

Given $f_{o} = 1.5$ m and $L = 1.56$ m.

Substituting the values, we get $1.56 = 1.5 + f_{e}$ .

$f_{e} = 1.56 - 1.5 = 0.06$ m.

The focal length of the eyepiece is $0.06$ m.

Answer: 0.06 m

Stream:MHT_CETSubject:PhysicsTopic:Geometrical OpticsSubtopic:Optical instruments

⏱ 2mℹ️ Source: PYQ_2024

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