Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsReflection at curved surfaceMedium2 minPYQ_2024

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If the distance between object and its two times magnified virtual image produced by a curved mirror is 15 cm , the focal length of the mirror must be:

Options:

Answer:

Solution:

Since, image is magnified. So, it is a concave mirror. $∴ m = 2 = \frac{- v}{u}$ $2 = \frac{- ( 15 - u )}{- u}$ $2 u = 15 - u$ $3 u = 15 \Rightarrow u = 5 cm$ $v = 15 - u = 15 - 5 = 10 cm$ Bymirror formula, $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$ $= \frac{1}{10} + \frac{1}{( - 5 )} = \frac{1 - 2}{10} = \frac{- 1}{10}$ $f = - 10 cm$

Stream:BITSATSubject:PhysicsTopic:Geometrical OpticsSubtopic:Reflection at curved surface

⏱ 2mℹ️ Source: PYQ_2024

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