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PhysicsGeometrical OpticsRefraction at plane surfaceHard2 minPYQ_2023
PhysicsHardnumerical

In a medium the speed of light wave decreases to 0.2 times to its speed in free space. The ratio of relative permittivity to the refractive index of the medium is x:1. The value of x is ______.

(Given speed of light in free space =3×108 m s-1 and for the given medium μr=1)

Answer:
5.00
Solution:

Speed of light in medium is related to speed of light in vacuum c and refractive index μ by v=cμ.

Then, we have μ=cv=c0.2c

μ=5

Refractive index in terms of relative permeability μrand relative permittivityεr  of the medium is stated as μ=ϵr μr

ϵr=μ2μr

 ϵrμ=μμr=5

Hence, the value of x=5.

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at plane surface
2mℹ️ Source: PYQ_2023

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