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PhysicsGeometrical OpticsRefraction at curved surface/LensEasy2 minPYQ_2023
PhysicsEasynumerical

The radius of curvature of each surface of a convex lens having refractive index1.8is20 cm. The lens is now immersed in a liquid of refractive index1.5. The ratio of power of lens in air to its power in the liquid will bex: 1. The value ofxis

Answer:
4.00
Solution:

The power of a lens is given by 

P1=1f

Using Lens Maker's formula,

P1=(1.81)1R11R2 and 

P2=1fimmersed =1.81.511R11R2

Hence, the ratio is,

P1P2=(1.81)1.81.51=0.8×1.50.3=4

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens
2mℹ️ Source: PYQ_2023

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