A light ray falls on a glass surface of refractive index 3 , at an angle 60 ° . The angle between the refracted and reflected rays would be:

From Snell's law, μ 1 sin i = μ 2 sin r ⇒ 1 × sin 60 ° = 3 sin r ⇒ r = 30 ° Angle between the refracted say and reflected say is θ = 180 ° - i + r = 90 °

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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at plane surfaceEasy2 minPYQ_2022

PhysicsEasysingle choice

A light ray falls on a glass surface of refractive index $\sqrt{3}$ , at an angle $60 °$ . The angle between the refracted and reflected rays would be:

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Answer:

Solution:

From Snell's law,

$μ_{1} \sin i = μ_{2} \sin r$

$\Rightarrow 1 \times \sin 60 ° = \sqrt{3} \sin r$

$\Rightarrow r = 30 °$

Angle between the refracted say and reflected say is

$θ = 180 ° - (i + r) = 90 °$

Stream:NEETSubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at plane surface

⏱ 2mℹ️ Source: PYQ_2022

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