Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsOptical instrumentsMedium2 minPYQ_2022

PhysicsMediumsingle choice

In a compound microscope, let ' $u_{0}$ ' and ' $v_{0}$ ' be the object distance and image distance respectively. The objective of focal length ' $f_{0}$ ' magnifies a tiny object into a real, inverted image. The linear magnification of the objective is

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Solution:

Using lens formula: $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$ And definition of magnification, $m = \frac{v}{u}$ Multiply lens formula with $u$ , $(\frac{u}{v}) - 1 = \frac{u}{f}$ $(\frac{1}{m}) - 1 = \frac{u}{f}$ $m = \frac{f}{( u + f )}$

Stream:MHT_CETSubject:PhysicsTopic:Geometrical OpticsSubtopic:Optical instruments

⏱ 2mℹ️ Source: PYQ_2022

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