Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensMedium2 minPYQ_2021

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A biconvex lens $(R_{1} = R_{2} = 30)$ has focal length equal to the focal length of concave mirror. The radius of curvature of concave mirror is [Refractive index of material of lens $= 1.6]$

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Solution:

For a biconvex lens $\frac{1}{f} = (μ - 1) (\frac{1}{R _{1}} - \frac{1}{R _{2}}) = (1.6 - 1) (\frac{1}{30} + \frac{1}{30}) = 0.6 \times \frac{2}{30} = \frac{1.2}{30} f = \frac{30}{1.2} = 25 cm$ Radius of concave mirror $= 2 f = 50 cm$

Stream:MHT_CETSubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: PYQ_2021

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