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PhysicsGeometrical OpticsTIR/Prism and DispersionHard2 minPYQ_2021
PhysicsHardmultiple choice

For a prism of prism angle θ=60°, the refractive indices of the left half and the right half are, respectively, n1 and n2n2n1 as shown in the figure. The angle of incidence i is chosen such that the incident light rays will have minimum deviation if n1=n2=n=1.5. For the case of unequal refractive indices, n1=n and n2=n+n (where n<<n), the angle of emergence e=i+e. Which of the following statement(s) is(are) correct?

Question diagram: For a prism of prism angle θ = 60 ° , the refractive indices

Options:(select one or more)

Answer:
B, C
Solution:

Given, n1=n2=n=32

In case of minimum deviation,

rm=A2=60°2=30°

and i=e

Applying expression for minimum deviation,

n=sinδmin+A2sinA232=sin(i)sin60°2sini=34,  cosi=74

If n1=n=32 and n2=n+n:

Angle of emergence, e=i+Δe

Applying Snell's law, we get,

1×sini=nsin30°

Then,

n+Δnsin30°=1sini+Δe

Solving both equations we get,12Δn=sini+Δe-sini

Δn2=sini+Δe-siniΔe×Δe

Now using the definition of derivative,

dsinidi=cosi

For small change, ei.

Therefore,

Δn2=cosiΔeΔn2=74ΔeΔnΔe=72=2.642

ΔnΔe=1.34>1Δn>Δe,

Hence, option (A) is incorrect.

Δn=1.34ΔeΔeΔn

Hence, option (B) is correct.

ΔnΔe=72If Δn=2.8×10-3,2.8×10-3Δe=72

Δe=5.6×10-37=7×0.8×10-3

Δe=2.64×0.8×10-3=2.11×10-3 rad

Option (C) is correct.

Stream:JEE_ADVSubject:PhysicsTopic:Geometrical OpticsSubtopic:TIR/Prism and Dispersion
2mℹ️ Source: PYQ_2021

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