Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensEasy2 minPYQ_2020

PhysicsEasynumerical

A plano-convex lens has a radius of curvature of the curved surface equal to $30 cm$ and a refractive index equal to $1.5$ , then what is the focal length (in $cm$ ) of the lens?

Answer:

60.00

Solution:

$\frac{1}{f} = (μ - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}}) R_{1} = \propto R_{2} = - 30 cm \frac{1}{f} = (1.5 - 1) (\frac{1}{\infty} - \frac{1}{- 30}) \frac{1}{f} = \frac{0.5}{30} f = 60 cm$

Subject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: PYQ_2020

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