Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsReflection at curved surfaceEasy2 minPYQ_2020

PhysicsEasysingle choice

A thin rod of $5 cm$ length is kept along the axis of a concave mirror of $10 cm$ focal length such that its image is real and magnified and one end touches the rod. Its magnification will be

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Answer:

Solution:

End $A$ of the rod acts as an object for mirror and $A'$ will be its image so $u = 2 f - l = 20 - 5 = 15 cm$

$∵$ $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$ $\Rightarrow \frac{1}{- 10} = \frac{1}{v} - \frac{1}{15} \Rightarrow v = - 30 cm .$

Now $m = \frac{Length of image}{Length of object} = \frac{(30 - 20)}{5} = 2$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Geometrical OpticsSubtopic:Reflection at curved surface

⏱ 2mℹ️ Source: PYQ_2020

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