Physics - Geometrical Optics Question with Solution | TestHub

For ${\mathrm{I}}_1$ applying lens formula

$\begin{array}{l}\frac{1}{v_1}-\frac{1}{-1}=\frac{1}{0.5}\\ \end{array}$

$v_1=1$

For $I_2$ applying condition of plane mirror

for final image ($I_3$) again applying lens formula

$\frac{1}{v_3}-\frac{1}{-3}=\frac{1}{0.5}$

$v_2=\frac{3}{5}$

The distance of final image from mirror

$D=\frac{3}{5}+3$

$D=2.6$

The image will be real (but it is given virtual in answer)