Physics - Geometrical Optics Question with Solution | TestHub

The velocity of light water in the material is

$v=v\mathrm{\lambda }\mathrm{ }\mathrm{ }\mathrm{ }\mathrm{ }\mathrm{ }\mathrm{ }\dots \left(\mathrm{i}\right)$

Refractive index of the material is

$\mathrm{\mu }=\frac{c}{v} \dots \left(\mathrm{i}\mathrm{i}\right)$

Where$c$is the speed of light in vacuum or air

or$\mathrm{\mu }=\frac{c}{v\mathrm{\lambda }} \dots \left(\mathrm{i}\mathrm{i}\mathrm{i}\right)$

Given,$v=2\times {10}^{14 }\mathrm{H}\mathrm{z}$,

$\mathrm{\lambda }=5000 \mathrm{\AA }=5000\times {10}^{-10}\mathrm{ }\mathrm{m}$

$c=3\times {10}^{\mathrm{8 }}\mathrm{m} {\mathrm{s}}^{-1}$

Hence, from Eq (iii), we get

$\mathrm{\mu }=\frac{3\times {10}^8}{2\times {10}^{14}\times 5000\times {10}^{-10}}=3.00$