Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsOptical instrumentsEasy2 minPYQ_2020

PhysicsEasynumerical

An astronomical telescope has objective and eyepiece of focal lengths $40 cm$ and $4 cm$ respectively. To view an object $200 cm$ away from the objective, at what distance the lenses must be separated (in $cm$ )?

Answer:

54.00

Solution:

$\frac{1}{V} - \frac{1}{- 200} = \frac{1}{40}$

$\frac{1}{V} = \frac{5}{5} \frac{1}{40} - \frac{1}{200}$

$= \frac{5}{200} - \frac{1}{200}$

$\frac{1}{V} = \frac{4}{200} = \frac{1}{50}$

$V = 50$

$∴ d = 50 + 4 = 54 c m$

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Optical instruments

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...