An object is placed at a distance of f 2 from a convex lens of focal length f . The image will be

1 v - 1 - f / 2 = 1 f 1 v = 1 f - 2 f = - 1 f or v = - f Again, m = v u = - f - f / 2 = 2 Clearly, the image is virtual and double the size

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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensEasy2 minPYQ_2020

PhysicsEasysingle choice

An object is placed at a distance of $\frac{f}{2}$ from a convex lens of focal length $f$ . The image will be

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Answer:

Solution:

$\frac{1}{v} - \frac{1}{- f / 2} = \frac{1}{f}$

$\frac{1}{v} = \frac{1}{f} - \frac{2}{f} = - \frac{1}{f}$

or $v = - f$

Again, $m = \frac{v}{u} = \frac{- f}{- f / 2} = 2$

Clearly, the image is virtual and double the size

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: PYQ_2020

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