Physics - Geometrical Optics Question with Solution | TestHub

According to the figure,

Given,$i=45°$

Let the angle between the reflected ray and refracted ray is



Apply Snell's law at the air-glass surface,

$\frac{\sin i}{\sin r}=\frac{n}{1}$

$\Rightarrow \frac{\sin 45°}{\sin r}=\sqrt{2}$

$\sin r=\frac{1}{\sqrt{2}\cdot \sqrt{2}}=\frac{1}{2}$

$\therefore r=30°$

From the diagram,$\theta =180-\left(i+r\right)$

$=180-\left(45°+30°\right)$

$=180°-75°=105°$