What is the angle of incidence for an equilateral prism of refractive index 3 so that the ray is parallel to the base inside the prism?

3 = sin ⁡ 60 ° - δ m 2 sin ⁡ 60 ° 2 3 2 = sin ⁡ 60 ° + δ m 2 sin ⁡ 60 ° = sin ⁡ 60 ° + δ m 2 Or 60 ° + δ m 2 = 60 ° Or δ m = 60 ° ; i = A + δ m 2 = 60 ° + 60 ° 2 = 60 °

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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsTIR/Prism and DispersionEasy2 minPYQ_2020

PhysicsEasysingle choice

What is the angle of incidence for an equilateral prism of refractive index $\sqrt{3}$ so that the ray is parallel to the base inside the prism?

Options:

Answer:

Solution:

$\sqrt{3} = \frac{\sin (\frac{60 ° - δ_{m}}{2})}{\sin (\frac{60 °}{2})}$

$\frac{\sqrt{3}}{2} = \sin (\frac{60 ° + δ_{m}}{2})$

$\sin 60 ° = \sin (\frac{60 ° + δ_{m}}{2})$

Or $\frac{60 ° + δ_{m}}{2} = 60 °$

Or $δ_{m} = 60 °; i = \frac{A + δ_{m}}{2} = \frac{60 ° + 60 °}{2} = 60 °$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Geometrical OpticsSubtopic:TIR/Prism and Dispersion

⏱ 2mℹ️ Source: PYQ_2020

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