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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensEasy2 minPYQ_2020

PhysicsEasysingle choice

A point object O is placed on the principal axis of a convex lens of focal length $f = 20 cm$ at a distance of 40 cm to the left of it. The diameter of the lens is 10 cm. An eye is placed 60 cm to right of the lens and a distance $h$ below the principal axis. The maximum value of $h$ to see the image is. (assume paraxial approximation to be valid here)

Options:

Answer:

Solution:

$\frac{1}{v} = \frac{1}{f} + \frac{1}{u}$

$= \frac{1}{20} - \frac{1}{40} = \frac{1}{40}$

v = 40 cm

To locate field of view ray passing through upper end should be used. At location of eye, its height should not be below 20 tan $θ$ from axis to see the image i.e., $20 (\frac{5}{40}) = 2.5 cm$

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: PYQ_2020

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