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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensEasy2 minPYQ_2020

PhysicsEasysingle choice

If the radius of curvature of the curved surface of a plano-convex lens is $50 cm$ , its focal length is $(μ = 1.5)$

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Answer:

Solution:

From lens maker's formula,

$\frac{1}{f} = (n - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}})$

Given, $n = 1.5$

$R_{1} = \infty$ (Plane surface)

$R_{2} = - 50 cm = - 0 .5 m$

$\frac{1}{f} = (1.5 - 1) \times \frac{1}{0.5}$

$= 0.5 \times \frac{1}{0.5} = 1 m$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: PYQ_2020

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