Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at plane surfaceHard2 minPYQ_2020
PhysicsHardmultiple choice

A beaker of radius r is filled with waterrefractive index 43 up to a height H as shown in the figure on the left. The beaker is kept on a horizontal table rotating with angular speed ω. This makes the water surface curved so that the difference in the height of water level at the centre and at the circumference of the beaker is hh≪H, h≪r, as shown in the figure on the right. Take this surface to be approximately spherical with a radius of curvature R. Which of the following is/are correct? (g is the acceleration due to gravity)

Options:(select one or more)

Answer:
A, D
Solution:

h=ω2r22g

r2+(R-h)2=R2

r2=R2-(R-h)2=(2R-h)h

r2=2Rh-h2

∴  R=r2+h22h       ......option (A)

For apparent depth, now

As r≪h,

R=r22h=gω2

Refraction formula,

1v-43(H-h)=1-4/3R

1v=13R+43(H-h)

Since H≫h,

1v=ω23g+43H=43H1+3H4×ω23g

⇒|v|=3H41+ω2H4g-1        .......option (D)

Stream:JEE_ADVSubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at plane surface
⏱ 2mℹ️ Source: PYQ_2020

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