Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsReflection at curved surfaceEasy2 minPYQ_2020

PhysicsEasysingle choice

A point object is placed on the principal axis of a concave mirror, at a distance of $15 cm$ from the pole. The radius of curvature of the mirror is $20 cm$ and the object is made to oscillate along the principal axis with an amplitude of $2 mm$ . The amplitude of its image will be

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Answer:

Solution:

Using mirror formula,

$\frac{1}{- 10} = \frac{1}{v} + \frac{1}{- 15} \Rightarrow v = - 30 cm$

$|Axial magnification| = \frac{V^{2}}{u^{2}} = {(\frac{30}{15})}^{2} = 4$

Amplitude of image = 4 x 2 = 8 mm.

Subject:PhysicsTopic:Geometrical OpticsSubtopic:Reflection at curved surface

⏱ 2mℹ️ Source: PYQ_2020

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