Physics - Geometrical Optics Question with Solution | TestHub

$\sin c=\frac{1}{\mu }$ $a{\mu }_{\mathrm{w}}=\frac{4}{3},a{\mu }_{\mathrm{g}}=\frac{3}{2},w{\mu }_{\mathrm{g}}=\frac{\mathrm{a}{\mu }_{\mathrm{g}}}{\mathrm{a}{\mu }_{\mathrm{w}}}=\frac{9}{8}$ Critical angle will be maximum when refractive index of the denser medium w.r.t. the rarer medium is minimum. $w{\mu }_8=\frac{9}{8}$ is minimum