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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A man's near point is $0.5 m$ and far point is $3 m$ . Power of spectacle lenses required for

(i) reading purposes

(ii) seeing distant objects, respectively are

Options:

Answer:

Solution:

For reading purpose

$u = - 25 c m, v = - 50 c m, f = ?$

$∴ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} = \frac{1}{50} + \frac{1}{25} = \frac{1}{50}$

$P = \frac{100}{f} = + 2 D$

For distinct vision,

$f^{'} =$ distance of far point $= - 3$ $m$

$P$ = $\frac{1}{f'} = - \frac{1}{3}$ $D$ = $-$ $0.33 D$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Geometrical OpticsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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