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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction+ReflectionMedium2 minPYQ_2020

PhysicsMediumsingle choice

A biconvex lens $(R_{1} = R_{2} = 20 cm)$ has focal length equal to focal length of concave mirror. The radius of curvature of concave mirror is [R.I. of glass lens $= 1 \cdot 5$ ]

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Solution:

$\frac{1}{f} = (n - 1) (\frac{1}{R _{1}} - \frac{1}{R _{2}}) n = 1.5, R_{1} = 20 cm, R_{2} = - 20 cm ∴ f = 20 cm$ for a concave mirror, $R = 2 f$ and it is negative. $∴ R = - 40 cm$

Stream:MHT_CETSubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction+Reflection

⏱ 2mℹ️ Source: PYQ_2020

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