A telescope, whose objective lens has an aperture of 1 mm for the wavelength of light 500 A ˚ , then limiting resolving power of the telescope is

Given: Aperture of objective lens ( a ) = 1 mm = 1 × 1 0 − 3 m Wavelength of light ( λ ) = 500 A ˚ = 500 × 1 0 − 10 m Limiting resolving power of telescope, d θ = a 1.22 λ = 1 × 1 0 − 3 1.22 × 500 × 1 0 − 10 = 6.1 × 1 0 − 5 rad

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PhysicsGeometrical OpticsOptical instrumentsEasy2 minPYQ_2019

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A telescope, whose objective lens has an aperture of $1 mm$ for the wavelength of light $500 \overset{˚}{A}$ , then limiting resolving power of the telescope is

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Given: Aperture of objective lens $(a) = 1 mm = 1 \times 1 0^{- 3} m$ Wavelength of light $(λ) = 500 \overset{˚}{A} = 500 \times 1 0^{- 10} m$ Limiting resolving power of telescope, $d θ = \frac{1.22 λ}{a} = \frac{1.22 \times 500 \times 1 0 ^{- 10}}{1 \times 1 0 ^{- 3}} = 6.1 \times 1 0^{- 5} rad$

Stream:AIIMSSubject:PhysicsTopic:Geometrical OpticsSubtopic:Optical instruments

⏱ 2mℹ️ Source: PYQ_2019

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