Physics - Geometrical Optics Question with Solution | TestHub

From Snell's law of refraction, $\frac{\sin i}{\sin r}=\frac{{\mu }_2}{{\mu }_1}=\frac{v_1}{v_2}$ Given, $v_1=3\times 10^8\mathrm{m}/\mathrm{s}$ $\begin{array}{rlrl}& & \frac{{\mu }_2}{{\mu }_1}& ={}^1{\mu }_2=1.5\\ \Rightarrow & & v_2& =\frac{v_1}{{}^1{\mu }_2}=\frac{3\times 10^8}{1.5}\mathrm{m}/\mathrm{s}\\ \therefore & & v_2=\frac{3\times 10^8}{3/2}=2\times 10^8\mathrm{m}/\mathrm{s}& \end{array}$