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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsTIR/Prism and DispersionMedium2 minPYQ_2016

PhysicsMediumsingle choice

The angle of incidence for a ray of light at a refracting surface of a prism is $45^{o}$ . The angle of prism is $60^{o}$ . If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are:

Options:

Answer:

Solution:

At minimum deviation $δ_{m i n} = 2 i - A$

$δ_{m i n} = 2 (45) - 60$

$δ_{m i n} = 30^{o}$

Refractive index of material is

$μ = \frac{\sin (\frac{δ_{m i n} + A}{2})}{\sin (\frac{A}{2})} = \frac{\sin (\frac{30 + 60}{2})}{\sin (30^{o})}$

$μ = \frac{\sin 45^{o}}{\sin 30^{o}} = \frac{\frac{1}{\sqrt{2}}}{\frac{1}{2}} = \sqrt{2}$

Stream:NEETSubject:PhysicsTopic:Geometrical OpticsSubtopic:TIR/Prism and Dispersion

⏱ 2mℹ️ Source: PYQ_2016

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