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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsTIR/Prism and DispersionMedium2 minPYQ_2015

PhysicsMediumsingle choice

The refracting angle of a prism is $A$ , and refractive index of the material of the prism is $\cot (\frac{A}{2})$ . The angle of minimum deviation is

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Answer:

Solution:

$μ = \frac{\sin (\frac{δ m + A}{2})}{\sin (\frac{A}{2})}$
$∵ μ = \cot (\frac{A}{2})$
$∴ \cot (\frac{A}{2}) = \frac{\sin (\frac{δ m + A}{2})}{\sin \frac{A}{2}}$
$\cos \frac{A}{2} = \sin (\frac{δ m + A}{2})$
$\frac{π}{2} - \frac{A}{2} = \frac{δ m + A}{2}$
$δ m = π - 2 A$

Stream:NEETSubject:PhysicsTopic:Geometrical OpticsSubtopic:TIR/Prism and Dispersion

⏱ 2mℹ️ Source: PYQ_2015

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