Physics - Geometrical Optics Question with Solution | TestHub

As situation can be diagrammatically as belowFrom law of reflection $$i=\theta$$ Now, $\theta +r+90^{\circ }=180^{\circ }$ $$\begin{array}{rl}\Rightarrow i+r+90^{\circ }& =180^{\circ }\\ r& =90^{\circ }-i\end{array}$$ Also, from Snell's law $\frac{\sin i}{\sin r}=\mu \Rightarrow \frac{\sin i}{\sin \left(90^{\circ }-i\right)}=\frac{\sin i}{\cos i}=\mu$ $\Rightarrow \tan i=\mu$