The focal lengths of objective lens and eye lens of a Galilean Telescope are respectively 30 cm and 3.0 cm. Telescope produces virtual, erect image of an object situated far away from it at least dist

Question

The focal lengths of objective lens and eye lens of a Galilean Telescope are respectively 30 cm and 3.0 cm. Telescope produces virtual, erect image of an object situated far away from it at least distance of distinct vision from the eye lens. In this condition the Magnifying Power of the Galilean Telescope should be :

Options:

Answer:

C

Solution:

$MP = \frac{- f_{0}}{f_{e}} (1 + \frac{f_{e}}{D})$

$= \frac{- 30}{- 3} (1 + \frac{|- 3|}{25})$

$= + 11.2$

TestHub · Accepted Answer

MP = - f ⁡ 0 f ⁡ e 1 + f ⁡ e D = - 3 0 - 3 1 + - 3 2 5 = + 11.2

Physics - Geometrical Optics Question with Solution | TestHub

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