Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensMedium2 minPYQ_2013

PhysicsMediumsingle choice

The given lens is broken into four parts and rearranged as shown. If the initial focal length is $f$ then after rearrangement the equivalent focal length is-

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Answer:

Solution:

Cutting a lens in transverse direction doubles their focal length i.e. $2 f$ . Using the formula of equivalent focal length, $\frac{1}{f} = \frac{1}{f _{1}} + \frac{1}{f _{2}} + \frac{1}{f _{3}} + \frac{1}{f _{4}}$ We get equivalent focal length as $f /2$

Stream:BITSATSubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: PYQ_2013

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