The frequency of a light wave in a material is 2 × 1 0 14 Hz and wavelength is 5000 A ˚ . The refractive index of material will be

Using, μ = v C Here, c = 3 × 1 0 8 m s − 1 v = v λ = 2 × 1 0 14 Hz × 5000 × 1 0 − 10 m = 1 × 1 0 8 m s − 1 ∴ μ = 1 × 1 0 8 m s − 1 3 × 1 0 8 m s − 1 = 3

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PhysicsGeometrical OpticsRefraction at plane surfaceMedium2 minPYQ_2013

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The frequency of a light wave in a material is $2 \times 1 0^{14} Hz$ and wavelength is $5000 \overset{˚}{A}$ . The refractive index of material will be

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Using, $μ = \frac{C}{v}$ Here, $c = 3 \times 1 0^{8} m s^{- 1}$ $v = v λ = 2 \times 1 0^{14} Hz \times 5000 \times 1 0^{- 10} m$ $= 1 \times 1 0^{8} m s^{- 1}$ $∴ μ = \frac{3 \times 1 0 ^{8} m s ^{- 1}}{1 \times 1 0 ^{8} m s ^{- 1}} = 3$

Stream:AIIMSSubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at plane surface

⏱ 2mℹ️ Source: PYQ_2013

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