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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensMedium2 minPYQ_2010

PhysicsMediumsingle choice

For a person near point of vision is $100 cm$ . Then the power of lens he must wear so as to have normal vision, should be

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Solution:

The power of lens $P = \frac{1}{f} = \frac{1}{v} - \frac{1}{u} = [\frac{1}{25} - \frac{1}{N.P.}]$ where N.P. = Near point of vision $P = [\frac{1}{25} - \frac{1}{100}] P = \frac{4 - 1}{100} = \frac{3}{100 cm} = \frac{3}{1 m} = 3 D$

Stream:AIIMSSubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: PYQ_2010

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