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PhysicsFluidBernoulli's theorem and applicationsMedium2 minQB

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Passage / Comprehension

The inner cross-sectional area of the fixed horizontal tube is A; its right-hand section has area KA, where K < 1. The two sections join smoothly without sharp turns. A liquid of density ρ and negligible viscosity is pushed by a piston on the left. The water leaving the tube hits a vertical wall and spreads into a tapering film.

Shared passage diagram

At what constant speed does the piston moves if external force has constant value F

Options:

Answer:

Solution:

$FVdt = \frac{dm}{2} [(\frac{V}{K})^{2} - V^{2}]$ $dm = ρ AVdt V \frac{2 F}{ρ A} (\frac{K ^{2}}{1 - K ^{2}})$

Stream:JEESubject:PhysicsTopic:FluidSubtopic:Bernoulli's theorem and applications

⏱ 2mℹ️ Source: QB

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